Question
Subtract the second polynomial from the first :
$x^2-9 x+\sqrt{3} ;-19 x+\sqrt{3}+7 x^2$
$x^2-9 x+\sqrt{3} ;-19 x+\sqrt{3}+7 x^2$
✓
Answer
$x^2-9 x+\sqrt{3}-\left(-19 x+\sqrt{3}+7 x^2\right)$
$=x^2-9 x+\sqrt{3}+19 x-\sqrt{3}-7 x^2$
$=x^2-7 x^2-9 x+19 x+\sqrt{3}-\sqrt{3}$
$=-6 x^2+10 x$
$=x^2-9 x+\sqrt{3}+19 x-\sqrt{3}-7 x^2$
$=x^2-7 x^2-9 x+19 x+\sqrt{3}-\sqrt{3}$
$=-6 x^2+10 x$
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