Question
Subtract the sum of $\left(8 a-6 a^2+9\right)$ and $\left(-10 a-8+8 a^2\right)$ from $-3$ .
✓
Answer
$\text { sum of }\left(8 a-6 a^2+9\right) \text { and }\left(-10 a-8+8 a^2\right)$
$=8 a-6 a^2+9+(-10 a)-8+8 a^2$
$=8 a-10 a-6 a^2+8 a^2+9-8$
$=-2 a+2 a^2+1$
$\text { Now }-3-\left(-2 a+2 a^2+1\right)$
$=\left(-3+2 a-2 a^2-1\right)$
$=-4+2 a-2 a^2$
$=8 a-6 a^2+9+(-10 a)-8+8 a^2$
$=8 a-10 a-6 a^2+8 a^2+9-8$
$=-2 a+2 a^2+1$
$\text { Now }-3-\left(-2 a+2 a^2+1\right)$
$=\left(-3+2 a-2 a^2-1\right)$
$=-4+2 a-2 a^2$
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