Question
Subtract: $(x - y + 3z)$ from $(2z - x - 3y)$
✓
Answer
$(x - y + 3z)$ from $(2z - x - 3y)$
$= (2z - x - 3y) - (x - y + 3z)$
$= 2z - x - 3y - x + y - 3z$
$= -x - x - 3y + y + 2z - 3z$
$= -2x - 2y - z$
$= (2z - x - 3y) - (x - y + 3z)$
$= 2z - x - 3y - x + y - 3z$
$= -x - x - 3y + y + 2z - 3z$
$= -2x - 2y - z$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Simplify and express each as a rational number: $\Big(\frac{-7}{8}\Big)^{-3}\times \Big(\frac{-7}{8}\Big)^2$
→ Express the following as a rational number:
$\Bigg\{\Big(\frac{4}{3}\Big)^{-1}-\Big(\frac{1}{4}\Big)^{-1}\Bigg\}^{-1}$
→$\Bigg\{\Big(\frac{4}{3}\Big)^{-1}-\Big(\frac{1}{4}\Big)^{-1}\Bigg\}^{-1}$
Find which of the following are in proportion? $33, 44, 66, 88$
→A freezing process requires that the room temperature he lowered from 32°C at the rate of 5°C every hour. What will be the room temperature 10 hours after the process begins?
Find the value of $x$ in each of the following figures, if /$\| m$.
→Find the simple interest, when:
Principal = ₹ 12000, $\quad$ Rate of Interest = 18% per annum $\quad$ and Time = 4 months.
→Principal = ₹ 12000, $\quad$ Rate of Interest = 18% per annum $\quad$ and Time = 4 months.
Find the mode and median of the following data
$
13, 16, 12, 14, 19, 12, 14, 13, 14 .
$
→$
13, 16, 12, 14, 19, 12, 14, 13, 14 .
$
Name the quadrilateral which have both line and rotational symmetry of order more than 1.
Simplify
$\frac{13}{11} \times \frac{-14}{5}+\frac{13}{11} \times \frac{-7}{5}+\frac{-13}{11} \times \frac{34}{5}$
→$\frac{13}{11} \times \frac{-14}{5}+\frac{13}{11} \times \frac{-7}{5}+\frac{-13}{11} \times \frac{34}{5}$
Fill in the blank with integer:
37 – (33 – _______) = 35
37 – (33 – _______) = 35