Question
Subtract:
$\left(x^2-y^2\right)$ from $\left(2 x^2-3 y^2+6 x y\right)$
$\left(x^2-y^2\right)$ from $\left(2 x^2-3 y^2+6 x y\right)$
✓
Answer
$\left(x^2-y^2\right)$ from $\left(2 x^2-3 y^2+6 x y\right)$
$=\left(2 x^2-3 y^2+6 x y\right)-\left(x^2-y^2\right)$
$=2 x^2-3 y^2+6 x y-x^2+y^2$
$=2 x^2-x^2-3 y^2+y^2+6 x y$
$=x^2-2 y^2+6 x y$
$=\left(2 x^2-3 y^2+6 x y\right)-\left(x^2-y^2\right)$
$=2 x^2-3 y^2+6 x y-x^2+y^2$
$=2 x^2-x^2-3 y^2+y^2+6 x y$
$=x^2-2 y^2+6 x y$
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