Subtraction of integers is: - Vidyadip

MCQ

Subtraction of integers is:

✓
Commutative but no associative.
B
Commutative and associative.
C
Associative but not commutative.
D
Neither commutative nor associative.

✓

Answer

Correct option: A.

Commutative but no associative.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q (1 Marks)" from Relations and Functions→Relations and Functions — all question types→Maths STD 12 Science question papers→Gujarat Board STD 12 Science question papers→Gujarat Board question paper generator→

Similar questions

$\int(3\text{x}^2-1)\text{dx:}$

The solution of the equation ${\sin ^{ - 1}}\left( {\frac{{dy}}{{dx}}} \right) = x + y$ is

Integrating factor of differential equation $\frac{d y}{d x}+y \tan x-\sec x=0$ is

The integral $\int\left(\frac{x}{x \sin x+\cos x}\right)^{2} d x$ is equal to

(where $C$ is a constant of integration)

An are $P Q$ of a circle subtends a right angle at its centre $O$. The mid point of the arc $P Q$ is $R$. If $\overline{O P}=\vec{u}, \overline{O R}=\vec{v}$ and $\overrightarrow{O Q}=\alpha \vec{u}+\beta \vec{v}$, then $\alpha, \beta^2$ are the roots of the equation

Let $f(x)$ be a polynomial function such that $f(x)+f^{\prime}(x)+f^{\prime \prime}(x)=x^{5}+64$. Then, the value of $\lim _{x \rightarrow 1} \frac{f(x)}{x-1}$

Consider the lines $L _1$ and $L _2$ given by

$L_1: \frac{ x -1}{2}=\frac{ y -3}{1}=\frac{ z -2}{2}$

$L _2: \frac{ x -2}{1}=\frac{ y -2}{2}=\frac{ z -3}{3}$

A line $L _3$ having direction ratios $1,-1,-2$, intersects $L _1$ and $L _2$ at the points $P$ and $Q$ respectively. Then the length of line segment $PQ$ is

If $\int\limits^1_0\text{f}(\text{x})\text{dx}=1,\int\limits^1_0\text{x}\text{f}(\text{x})\text{dx}=\text{a},\int\limits^1_0\text{x}^2\text{f}(\text{x})\text{dx}=\text{a}^2,$ then $\int\limits^1_0(\text{a}-\text{x})^2\text{f(x)}\text{dx}$ equals :

The differential equation whose solution is $A{x^2} + B{y^2} = 1$ where $A$ and $B$ are arbitrary constants is of

$\int\limits^\frac{\pi}{2}_0\frac{1}{1+\tan\text{x}}\text{dx}$ is equal to: