MCQ
Sulphur on boiling with $NaOH$ solution gives
- A$N{a_2}{S_2}{O_3} + NaHS{O_3}$
- ✓$N{a_2}{S_2}{O_3} + N{a_2}S$
- C$N{a_2}S{O_3}$$ + {H_2}S$
- D$N{a_2}S{O_3} + S{O_2}$
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Which compound reacts with $Ag$ powder to give $X$

Assume Planck's constant $( h )=6.4 \times 10^{-34}\,Js$ Speed of light $( c )=3.0 \times 10^8\,m / s$ and Avogadro's constant $\left( N _{ A }\right)=6 \times 10^{23} / mol$
$C{{H}_{3}}-C\equiv CH\xrightarrow[{{H}_{2}}S{{O}_{4}}]{HgS{{O}_{4}}}A\xrightarrow{NaB{{H}_{4}}}B$