MCQ
$\sum_{\mathrm{k}=0}^{20}\left({ }^{20} \mathrm{C}_{\mathrm{k}}\right)^{2}$ is equal to :
- A${ }^{40} \mathrm{C}_{21}$
- B${ }^{40} \mathrm{C}_{19}$
- ✓${ }^{40} \mathrm{C}_{20}$
- D${ }^{41} \mathrm{C}_{20}$
sum of suffix is const. so summation will be ${ }^{40} \mathrm{C}_{20}$
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