- A$-3\pi $
- B$3 + 2\pi$
- ✓$3\pi $
- D$2 - 3\pi$
$f^{\prime}(\mathrm{x})=\frac{-1}{\sqrt{1-\mathrm{x}^{2}}}-\frac{2}{1+\mathrm{x}^{2}}-6 \mathrm{x}^{2}-4<0$
$f(\mathrm{x})$ is decreasing function
$\therefore $ ${\text { Min. value }=0+\frac{\pi}{2}-2-4} $
${\mathrm{m}=\frac{\pi}{2}-6}$
Max value $=\pi+\frac{3 \pi}{2}+2+4$
$M=6+\frac{5 \pi}{2}$
$\mathrm{m}+\mathrm{M}=3 \pi$
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$(1)$ $a+b=3$
$(2)$ $\operatorname{det}\left(\operatorname{adj} M ^2\right)=81$
$(3)$ $(\operatorname{adj} M)^{-1}+\operatorname{adj} M^{-1}=-M$
$(4)$ If $M \left[\begin{array}{l}\alpha \\ \beta \\ \gamma\end{array}\right]=\left[\begin{array}{l}1 \\ 2 \\ 3\end{array}\right]$, then $\alpha-\beta+\gamma=3$

($1$) The value of $\frac{625}{4} p _1$ is
($2$) The value of $\frac{125}{4} p _2$ is
Give the answer or queution ($1$) and ($2$)