MCQ
Sum of the absolute deviations remains minimum with respect to
  • A
    mean
  • median
  • C
    mode
  • D
    geometric mean

Answer

Correct option: B.
median
b
Minimum deviation (MD) from mean $=\frac{\sum|X-\bar{X}|}{n}$

MD from median $=\frac{\sum \mid X-\text { median } \mid}{n}$

MD from mode $=\frac{\sum \mid X-\text { mode } \mid}{n}$

Since median $>$ mean $(\bar{X})$ and median $>$ mode.

So, It is clear that the mean deviation from median has the least value.

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