MCQ
$\sum_{k=1}^{11}\left(2+3^k\right)=$
- A$\frac{41+3^{10}}{2}$
- B$\frac{41+3^{12}}{2}$
- C$41+3^{12}$
- D$\frac{44+3^{12}}{2}$
✓
Answer
Self
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