_ m = 1 ^n m^2 is equal to - Vidyadip

MCQ

$\sum\limits_{m = 1}^n {{m^2}} $ is equal to

A
$\frac{{m(m + 1)}}{2}$
B
$\frac{{m(m + 1)(2m + 1)}}{6}$
✓
$\frac{{n(n + 1)(2n + 1)}}{6}$
D
$\frac{{n(n + 1)}}{2}$

✓

Answer

Correct option: C.

$\frac{{n(n + 1)(2n + 1)}}{6}$

c
(c) It is nothing but $\sum n^2$ $= \frac{{n(n + 1)(2n + 1)}}{{6}}$

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