- vA > vB > vC
- vA < vB < vC
- vA = vB = vC
- $\text{v}_\text{B}=\frac{1}{2}(\text{v}_\text{A}+\text{v}_\text{C})$
$\text{v}_\text{A}>\text{v}_\text{B}>\text{v}_\text{C}$
$\text{v}_\text{B}=\frac{1}{2}(\text{v}_\text{A}+\text{v}_\text{C})$
Explanation:
Since the speed of light is a universal constant,
$\text{v}_\text{A}=\text{v}_\text{B}=\text{v}_\text{C}=3\times 10^8\text{m/s}$
$\text{v}_\text{B}=\frac{1}{2}(\text{u}_\text{A}+\text{u}_\text{C})$ This expression also implies that vA = vB = vC
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(a) 440 Ω |
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(a) |
(b) |
(c) |
(d) |
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(a) 100 eV |
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(a) Velocity of light is constant in all media |
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(b) Velocity of light in vacuum is maximum
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(c) Velocity of light is same in all reference frames |
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(d) Laws of nature have identical form in all reference frames |