then \({n_A} = n + \frac{{3n}}{{100}} = \frac{{103n}}{{100}}\)
and \({n_B} = n - \frac{{2n}}{{100}} = \frac{{98}}{{100}}\)
but \({n_A} - {n_B} = 5\)
==> \(\frac{{5n}}{{100}} = 5\)
==> \(n = 100\,Hz\)
\( \therefore\) \({n_A} = \frac{{(103)(100)}}{{100}} = 103\,Hz\)
$[\,dB$ માં લબ્ધિ $\left.=10 \log _{10}\left(\frac{ P _{ o }}{ P _{i}}\right)\right]$