MCQ
${\tan ^{ - 1}}\frac{{1 - {x^2}}}{{2x}} + {\cos ^{ - 1}}\frac{{1 - {x^2}}}{{1 + {x^2}}} = $
- A$\frac{\pi }{4}$
- ✓$\frac{\pi }{2}$
- C$\pi $
${\tan ^{ - 1}}\frac{{1 - {x^2}}}{{2x}} + {\cos ^{ - 1}}\frac{{1 - {x^2}}}{{1 + {x^2}}}$
$ = {\tan ^{ - 1}}\left( {\frac{{1 - {{\tan }^2}\theta }}{{2\tan \theta }}} \right) + {\cos ^{ - 1}}\left( {\frac{{1 - {{\tan }^2}\theta }}{{1 + {{\tan }^2}\theta }}} \right)$
$ = {\tan ^{ - 1}}(\cot 2\theta ) + {\cos ^{ - 1}}(\cos 2\theta )$
$ = \frac{\pi }{2} - 2\theta + 2\theta = \frac{\pi }{2}$.
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
$\log2-1$
$\log2$
$\log4-1$
$-\log2$