MCQ
$\tan ^{-1}\left(\frac{1+\sqrt{3}}{3+\sqrt{3}}\right)+\sec ^{-1}\left(\sqrt{\frac{8+4 \sqrt{3}}{6+3 \sqrt{3}}}\right)$ is equal to $.........$
- A$\frac{\pi}{4}$
- B$\frac{\pi}{2}$
- ✓$\frac{\pi}{3}$
- D$\frac{\pi}{6}$
$=\tan ^{-1}\left(\frac{1}{\sqrt{3}}\right)+\sec ^{-1}\left(\frac{2}{\sqrt{3}}\right)=\frac{\pi}{3}$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
$(1,1)(-1,1),(1,-1),(-1,-1),(-2,1)(2,-1),(-1,2)$ and $(-2,-1)$