Question
$\tan^{-1}\sqrt{3}-\sec^{-1}(-2)\ \text{is equal to}:$ 
  1. ${\pi}$
  2. $-\frac{\pi}{3}$
  3. $\frac{\pi}{3}$
  4. $\frac{2\pi}{3}$

Answer

  1. $-\frac{\pi}{3}$
$\tan^{-1}(\sqrt{3})=\text{x}$
$\sqrt{3}=\tan\text{x}$
$\tan\frac{\pi}{3}=\tan\text{x}$
$\frac{\pi}{3}=\text{x}$
$\text{or x}=\frac{\pi}{3}$
$\text{Similarly}\ \sec^{-1}(-2)=\text{y}$
$-2=\sec\text{y}$
$\sec\frac{2\pi}{3}=\sec\text{y}$
$\text{y}=\frac{2\pi}{3}$
$\text{Now}\ \tan^{-1}\sqrt{3}-\sec^{-1}(-2)=\text{x}-\text{y}$
$=\frac{\pi}{3}-\frac{2\pi}{3}$
$-\frac{\pi}{3}$

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