3A - 2A - A = - Vidyadip

MCQ

$\tan 3A - \tan 2A - \tan A = $

✓
$\tan 3A\tan 2A\tan A$
B
$ - \tan 3A\tan 2A\tan A$
C
$\tan A\tan 2A - \tan 2A\tan 3A - \tan 3A\tan A$
D
None of these

✓

Answer

Correct option: A.

$\tan 3A\tan 2A\tan A$

a
(a) Since $\tan \,\,3A = \frac{{\tan A + \tan 2A}}{{1 - \tan A\,\,\tan 2A}}$

$ \Rightarrow \,\,\tan \,\,3A - \tan \,\,2A - \tan A = \tan \,\,3A\,\tan \,\,2A\,\,\tan A$.

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