MCQ
tan 3A - tan 2A - tan A =
- ✓tan 3A tan 2A tan A
- B- tan 3A tan 2A tan A
- Ctan A tan 2A - tan 2A tan 3A
- Dtan 2A tan 3A - tan A tan 2A
✓
Answer
Correct option: A.
tan 3A tan 2A tan A
(A)
Since $\tan 3 A=\frac{\tan A+\tan 2 A}{1-\tan A \tan 2 A}$
$\Rightarrow \tan 3 A-\tan 2 A-\tan A$
$=\tan 3 A \tan 2 A \tan A$
Since $\tan 3 A=\frac{\tan A+\tan 2 A}{1-\tan A \tan 2 A}$
$\Rightarrow \tan 3 A-\tan 2 A-\tan A$
$=\tan 3 A \tan 2 A \tan A$
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