MCQ
$\tan 5x\tan 3x\tan 2x = $
  • $\tan 5x - \tan 3x - \tan 2x$
  • B
    $\frac{{\sin 5x - \sin 3x - \sin 2x}}{{\cos 5x - \cos 3x - \cos 2x}}$
  • C
    $0$
  • D
    None of these

Answer

Correct option: A.
$\tan 5x - \tan 3x - \tan 2x$
a
(a) We have $5x = 3x + 2x $

$\Rightarrow \tan 5x = \tan (3x + 2x)$

==> $\tan 5x = \frac{{\tan 3x + \tan 2x}}{{1 - \tan 3x\tan 2x}}$

==>$\tan 5x - \tan 5x\tan 3x\tan 2x = \tan 3x + \tan 2x$

==> $\tan 5x\tan 3x\tan 2x = \tan 5x - \tan 3x - \tan 2x$.

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