MCQ
tan A बराबर होगा ?
- ✓$\cot \left(90^{\circ}-\mathrm{A}\right)$
- B$\sec \left(90^{\circ}-\mathrm{A}\right)$
- C$\tan \left(90^{\circ}-\mathrm{A}\right)$
- D$\cot \left(90^{\circ}-\mathrm{A}\right)$
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