MCQ
tan A बराबर होगा ?
  • $\cot \left(90^{\circ}-\mathrm{A}\right)$
  • B
    $\sec \left(90^{\circ}-\mathrm{A}\right)$
  • C
    $\tan \left(90^{\circ}-\mathrm{A}\right)$
  • D
    $\cot \left(90^{\circ}-\mathrm{A}\right)$

Answer

Correct option: A.
$\cot \left(90^{\circ}-\mathrm{A}\right)$
a

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