MCQ
$\tan A +\cot \left(180^{\circ}+ A \right)+\cot \left(90^{\circ}+ A \right) +\cot \left(360^{\circ}- A =\right)$
  • $0$
  • B
    $2 \tan A$
  • C
    $2 \cot A$
  • D
    $2(\tan A-\cot A)$

Answer

Correct option: A.
$0$
(A)
$\tan A +\cot \left(180^{\circ}+ A \right)+\cot ( \left.90^{\circ}+ A \right) +\cot \left(360^{\circ}- A \right)$
$=\tan A +\cot A -\tan A -\cot A =0$

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