MCQ
$\tan \frac{{2\pi }}{5} - \tan \frac{\pi }{{15}} - \sqrt 3 \tan \frac{{2\pi }}{5}\tan \frac{\pi }{{15}} = . .$
- A$ - \sqrt 3 $
- B$\frac{1}{{\sqrt 3 }}$
- C$1$
- ✓$\sqrt 3 $
$ \Rightarrow \,\,\tan \frac{{6\pi }}{{15}} - \tan \frac{\pi }{{15}} = \sqrt 3 + \sqrt 3 \,\tan \frac{{6\pi }}{{15}}\tan \frac{\pi }{{15}}$
$ \Rightarrow \,\,\tan \frac{{6\pi }}{{15}} - \tan \frac{\pi }{{15}} - \sqrt 3 \,\tan \frac{{6\pi }}{{15}}\tan \frac{\pi }{{15}} = \sqrt 3 $
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.