MCQ
$\tan \frac{A}{2}$ is equal to
- A$ \pm \sqrt {\frac{{1 - \sin A}}{{1 + \sin A}}} $
- B$ \pm \sqrt {\frac{{1 + \sin A}}{{1 - \sin A}}} $
- ✓$ \pm \sqrt {\frac{{1 - \cos A}}{{1 + \cos A}}} $
- D$ \pm \sqrt {\frac{{1 + \cos A}}{{1 - \cos A}}} $
$= \frac{{\sin (A/2)}}{{\cos (A/2)}} $
$= \pm \sqrt {\frac{{(1 - \cos A)/2}}{{(1 + \cos A)/2}}} $
$= \pm \sqrt {\frac{{1 - \cos A}}{{1 + \cos A}}} $.
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