MCQ
$\tan \left(2 \tan ^{-1}\left(\frac{3}{5}\right)+\sin ^{-1}\left(\frac{5}{13}\right)\right)$ ની કિમંત મેળવો.
- A$\frac{-291}{76}$
- B$\frac{-181}{69}$
- C$\frac{151}{63}$
- D$\frac{220}{21}$
$\tan ^{-1} \frac{\frac{6}{5}}{1-\frac{9}{25}}=\underbrace{\tan ^{-1} \frac{15}{8}+\tan ^{-1} \frac{5}{12}}_{x\,>\,0, y\,>\,0, x y\,<\,1}$
$\tan ^{-1} \frac{\frac{15}{8}+\frac{5}{12}}{1-\frac{15}{8} \cdot \frac{5}{12}}=\tan ^{-1} \frac{220}{21}$
$\tan \left(\tan ^{-1} \frac{220}{21}\right)=\frac{220}{21}$
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