Question
$ \tan^{−1}\sqrt{3}+\sec−12–\cos−^{1}1$ is equal to ________.
  1. 0
  2. $ \frac{2}{π3}$
  3. $ \frac{\pi}{3}$
  4. $ \frac{\pi}{4}$

Answer

  1. $ \frac{2}{π3}$
solution:
$\tan^{-1}\sqrt{3}=\frac{\pi}{3},\sec^{-1}2,\cos^{-1}1=0$
$ ∴\tan^{−1}\sqrt{13}+\sec^{−1}2−\cos^{−1}1=\frac{π}{3}+\frac{π}{3}−0$
$ =\frac{2π}{3}$

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