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Inverse Trigonometric Functions — Maths STD 12 Science — Question

Gujarat BoardEnglish MediumSTD 12 ScienceMathsInverse Trigonometric Functions1 Mark
MCQ
$ \tan^{−1}\sqrt{3}+\sec−12–\cos−^{1}1$ is equal to $...........$
  • A
    $0$
  • ✓
    $ \frac{2}{\pi^3}$
  • C
    $ \frac{\pi}{3}$
  • D
    $ \frac{\pi}{4}$
✓

Answer

Correct option: B.
$ \frac{2}{\pi^3}$
$\tan^{-1}\sqrt{3}=\frac{\pi}{3},\sec^{-1}2,\cos^{-1}1=0$
$ \therefore \tan^{−1}\sqrt{13}+\sec^{−1}2−\cos^{−1}1$
$=\frac{\pi }{3}+\frac{\pi }{3}−0$
$ =\frac{2\pi }{3}$

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