MCQ
$\frac{\tan35^\circ}{\cot55^\circ}+\frac{\cot78^\circ}{\tan12^\circ}=?$
  • A
    $0$
  • B
    $1$
  • $2$
  • D
    None of these.

Answer

Correct option: C.
$2$
$\frac{\tan35^\circ}{\cot55^\circ}+\frac{\cot78^\circ}{\tan12^\circ}$
$=\frac{\tan(90^\circ-55^\circ)}{\cot55^\circ}+\frac{\cot78^\circ}{\tan(90^\circ-78^\circ)}$
$=\frac{\cot55^\circ}{\cot55^\circ}+\frac{\cot78^\circ}{\cot78^\circ}$
$=1+1$
$=2$

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