Ten students are seated at random in a row. The probability that … - Vidyadip

MCQ

Ten students are seated at random in a row. The probability that two particular students are not seated side by side is

✓
$\frac{4}{5}$
B
$\frac{3}{5}$
C
$\frac{2}{5}$
D
$\frac{1}{5}$

✓

Answer

Correct option: A.

$\frac{4}{5}$

a
(a) Total ways $ = 10\,\,!$

Two boys can sit side by side in $2 \times 9\,\,!$ ways.

So probaibility $ = \frac{{2 \times 9\,\,!}}{{10\,\,!}} = \frac{1}{5}$

Thus the probability that they are not seated together is $1 - \frac{1}{5} = \frac{4}{5}.$

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