- AThey have highest molecular mass.
- BThey do not form hydrogen bonds.
- CThey are more polar in nature.
- DThey are most basic in nature.
Explanation:
Primary and secondary amines can form hydrogen bonds whereas tertiary amines fail to do so. Hence, their boiling points are lowest.
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
(Nearest integer)
[Use : Molal Freezing point depression constant of water $\left.=1.86 \,\mathrm{~K} \,\mathrm{~kg} \,\mathrm{~mol}^{-1}\right]$
Freezing Point of water $=273\, \mathrm{~K}$
Atomic masses : $\mathrm{C}: 12.0\, \mathrm{u}, \mathrm{O}: 16.0\, \mathrm{u}, \mathrm{H}: 1.0\, \mathrm{u}]$
$(a)$ Peroxide ion as well as dioxygen molecule both are paramagnetic species
$(b)$ In set of isomers, $[Cr(H_2O)_6]Cl_3$ and $[CrCl(H_2O) _5]Cl_2 . H_2O,$ both compounds can easily loose water molecule on treatment with cone. $H_2SO_4$
$(c)$ During transformation $NO \to NO^+$ , bond length and magnetic behaviour decreases
$(d)$ An ether is more volatile than alcohol both having same molecular formula