a^3+b^3c^3-3abc a^2+b^2c^2-ab-bc-ca = ____ - Vidyadip

MCQ

$\frac{\text{a}^3+\text{b}^3\text{c}^3-3\text{abc}}{\text{a}^2+\text{b}^2\text{c}^2\text{-ab}-\text{bc}-\text{ca}}= \text{____}$

A
$0$
B
$1$
✓
$a + b + c$
D
None.

✓

Answer

Correct option: C.

$a + b + c$

$a + b + c$

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