MCQ
$(\text{cosec }\theta-\sin\theta)(\sec\theta-\cos\theta)(\tan\theta+\cot\theta)$ is equal to :
  • A
    $0$
  • $1$
  • C
    $-1$
  • D
    None of these.

Answer

Correct option: B.
$1$
$(\text{cosec }\theta-\sin\theta)(\sec\theta-\cos\theta)(\tan\theta+\cot\theta)$
$=\Big(\frac{1}{\sin\theta}-\sin\theta\Big)\Big(\frac{1}{\cos\theta}-\cos\theta\Big)$
$\Big(\frac{\sin\theta}{\cos\theta}+\frac{\cos\theta}{\sin\theta}\Big)$
$=\frac{1-\sin^2\theta}{\sin\theta}\times\frac{1-\cos^2\theta}{\cos\theta}\times\frac{\sin^2\theta+\cos^2\theta}{\sin\theta\cos\theta}$
$=\frac{\cos^2\theta}{\sin\theta}\times\frac{\sin^2\theta}{\cos\theta}\times\frac{1}{\sin\theta\cos\theta}$
$=\frac{\sin^2\theta\cos^2\theta}{\sin^2\theta\cos^2\theta}=1$

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