MCQ
$\text{f}(\text{x})=\frac{3\text{x}^2+\text{ax}+\text{a}+1}{\text{x}^2+\text{x}-2}$ and $\lim_\limits{\text{x} \rightarrow -2}\text{f}(\text{x})$ exists. Then the value of $(a - 4)$ is?
- ✓$9$
- B$10$
- C$11$
- D$12$
✓
Answer
Correct option: A.
$9$
$\text{f}(\text{x})=\frac{3\text{x}^2+\text{ax}+\text{a}+1}{\text{x}^2+\text{x}-2}$
As $0 x \rightarrow -2, D^r\rightarrow 0$.
Hence, as $x \rightarrow -2, N^r\rightarrow 0$.
Therefore, $12 - 2a + a + 1 = 0$ or $a = 13$
Hence, option A is correct.
As $0 x \rightarrow -2, D^r\rightarrow 0$.
Hence, as $x \rightarrow -2, N^r\rightarrow 0$.
Therefore, $12 - 2a + a + 1 = 0$ or $a = 13$
Hence, option A is correct.
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