MCQ
$\text{f}(\text{x})=\sin +\sqrt{3}\cos\text{x}$ is maximum when $x =$
  • A
    $\frac{\pi}{3}$
  • B
    $\frac{\pi}{4}$
  • $\frac{\pi}{6}$
  • D
    $0$

Answer

Correct option: C.
$\frac{\pi}{6}$
$\text{f}(\text{x})=\sin +\sqrt{3}\cos\text{x}$
$\Rightarrow\text{f}'(\text{x})=\cos\text{x}-\sqrt{3}\sin\text{x}$
For maxima or maxima,
$f\ '(x) = 0$
$\cos\text{x}-\sqrt{3}\sin\text{x}=0$
$\Rightarrow\ \tan\text{x}=\frac{1}{\sqrt{3}}$
$\Rightarrow\text{x}=\frac{\pi}{6}$
$\text{f}''\Big(\frac{\pi}{6}\Big)=-\sin\frac{\pi}{6}-\sqrt{3}\cos\frac{\pi}{6}$
$=\frac{-1-\sqrt{3}}{2} < 0$
function has local maima at $\text{x}=\frac{\pi}{6}$

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