Question
$\text{if} \ \text{A}'=\begin{bmatrix}3&4\\-1&2\\0&1\end{bmatrix},\text{and}\ \text{B}=\begin{bmatrix}-1&2&1\\1&2&3\end{bmatrix},\text{then verify that}$
  1. $\text{(A+B)}'=\text{A}'+\text{B}'$
  2. $\text{(A}-\text{B)}'=\text{A}'-\text{B}'$

Answer

  1. It is know that $ \text{A} = (\text{A}')'$
Therefore, we have:

$\text{A}=\begin{bmatrix}3&-1&0\\4&2&1\end{bmatrix} $

$ \text{B}'=\begin{bmatrix}-1&1\\2&2\\1&3\end{bmatrix}$

$\text{A + B}=\begin{bmatrix}3&-1&0\\4&2&1\end{bmatrix}+\begin{bmatrix}-1&2&1\\1&2&3\end{bmatrix}=\begin{bmatrix}2&1&1\\5&4&4\end{bmatrix}$

$\therefore\text{(A + B)}'=\begin{bmatrix}2&5\\1&4\\1&4\end{bmatrix}$

$\text{A}'+\text{B}'=\begin{bmatrix}3&4\\-1&2\\0&1\end{bmatrix}+\begin{bmatrix}-1&1\\2&2\\1&3\end{bmatrix}=\begin{bmatrix}2&5\\1&4\\1&4\end{bmatrix}$

Thus, we have verify that $ (\text{A} + \text{B})' = \text{A}' + \text{B}'$
  1. $\text{A} -\text{B}=\begin{bmatrix}3&-1&0\\4&2&1\end{bmatrix}-\begin{bmatrix}-1&2&1\\1&2&3\end{bmatrix}=\begin{bmatrix}4&-3&-1\\3&0&-2\end{bmatrix}$
$\therefore\text{(A} - \text{B})'=\begin{bmatrix}4&3\\-3&0\\-1&-2\end{bmatrix}$

$\text{A}' - \text{B}'=\begin{bmatrix}3&4\\-1&2\\0&1\end{bmatrix}\begin{bmatrix}-1&1\\2&2\\1&3\end{bmatrix}=\begin{bmatrix}4&3\\-3&0\\-1&-2\end{bmatrix}$

Thus, we have verify that $ (\text{A} - \text{B})' = \text{A}' - \text{B}'$

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