Question
$\frac{\text{y}-(4-3\text{y})}{2\text{y}-(3+4\text{y})}=\frac{1}{5}$
✓
Answer
Given, $\frac{\text{y}-(4-3\text{y})}{2\text{y}-(3+4\text{y})}=\frac{1}{5}$$5(y - 4 + 3y) = 2y - 3 - 4y$
$5(4y - 4) = -3 - 2y$
$20y - 20 = -3 - 2y$
$20y + 2y = 20 - 3$
$22y = 17$
$\frac{22\text{y}}{22}=\frac{17}{22}$
$\text{y}=\frac{17}{22}$
$5(4y - 4) = -3 - 2y$
$20y - 20 = -3 - 2y$
$20y + 2y = 20 - 3$
$22y = 17$
$\frac{22\text{y}}{22}=\frac{17}{22}$
$\text{y}=\frac{17}{22}$
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