MCQ
Thallium shows different oxidation states because
- AIt is a transition metal
- ✓Of inert-pair effect
- COf its high reactivity
- DOf its amphoteric character
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(Atomic numbers $Ce =58, Gd =64$ and $Eu =63 .)$
$(a)$ $\left( NH _{4}\right)_{2}\left[ Ce \left( NO _{3}\right)_{6}\right]$
$(b)$ $Gd \left( NO _{3}\right)_{3}$ and
$(c)$ $Eu \left( NO _{3}\right)_{3}$
Answer is :
