
The above potential energy curve is given for the formation of H2 molecule as a function of internuclear distance of H-atoms. At what point in the curve H, is found in the most stable state?
- AA
- BB
- CC
- D

Explanation:
At C point in the curve, H2 is found in the most stable state due to minimum energy, as the energy gets released when bond is formed between two hydrogen atoms.
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$(A)$ The $pH$ of $1 \times 10^{-8}\,M\,HCl$ solution is $8$.
$(B)$ The conjugate base $H _2 PO _4^{-}$is $HPO _4{ }^{2-}$.
$(C)$ $K _{ w }$ increases with increase in temperature.
$(D)$ When a solution of weak monoprotic acid is titrated against a strong base at half neutralisation point, $pH =\frac{1}{2} pK _{ a }$
Choose the correct answer from the option given below.

$1 \mathrm{~mol}$ of an ideal gas is kept in a cylinder, fitted with a piston, at the position $\mathrm{A}$, at $18^{\circ} \mathrm{C}$. If the piston is moved to position $B$, keeping the temperature unchanged, then ' $x$ ' $L$ atm work is done in this reversible process.
$\mathrm{x}=$ . . . . . . $\mathrm{L} \mathrm{atm.} \mathrm{(nearest} \mathrm{integer)}$
[Given : Absolute temperature $={ }^{\circ} \mathrm{C}+273.15$, $\left.\mathrm{R}=0.08206 \mathrm{~L} \mathrm{~atm} \mathrm{~mol}^{-1} \mathrm{~K}^{-1}\right]$