The acceleration displacement graph of a particle executing $SHM$ is shown in figure. The time period of simple harmonic motion is
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$a=\omega^{2} x$
$\Rightarrow \frac{a}{x}=\omega^{2}=\tan 37^{\circ}=\frac{3}{4}$
$\Rightarrow \frac{4 \pi^{2}}{\mathrm{T}^{2}}=\frac{3}{4} \Rightarrow \mathrm{T}=\frac{4 \pi}{\sqrt{3}}$ $s$
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