MCQ
The acceleration due to gravity on moon is ${ }^{\prime}(1 / 6)^{\wedge}$ "th"" times the acceleration due to gravity on earth. If the ratio of the density of earth ' $\rho_e$ ' to the density of moon ' $\rho_m$ ' is ' $5 / 3$ ', then the radius of moon ' $R_m$ ' in terms of the radius of earth ' $R_e$ ' is...............
- A$`(3/18)R_e`$
- B$`(1/(2sqrt3))R_e`$
- ✓$`(5/18)R_e`$
- D$`(7/6)R_e`$