The acceleration of a particle in S.H.M. is - Vidyadip

MCQ

The acceleration of a particle in S.H.M. is

A
Always zero
B
Always constant
✓
Maximum at the extreme position
D
Maximum at the equilibrium position

✓

Answer

Correct option: C.

Maximum at the extreme position

(c) Acceleration $=\omega^2 a$ at extreme position is maximum.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "MCQ" from Simple Harmonic Motion→Simple Harmonic Motion — all question types→JEE physics STD 12 Science question papers→CBSE Board STD 12 Science question papers→CBSE Board question paper generator→

Similar questions

Two plane mirrors are at $45^{\circ}$ to each other. If an object is placed between them, then the number of images will be

What is the de-Broglie wavelength of the $\alpha$-particle accelerated through a potential difference $V$

Two identical containers $A$ and $B$ with frictionless pistons contain the same ideal gas at the same temperature and the same volume $V$. The mass of the gas in $A$ is $m_A$ and that in $B$ is $m_B$. The gas in each cylinder is now allowed to expand isothermally to the same final volume $2 \mathrm{~V}$. The changes in the pressure in $A$ and $B$ are found to be $\Delta P$ and $1.5 \Delta P$ respectively. Then

In a wave motion $y=a \sin (k x-\omega t), y$ can represent

A $150 m$ long train is moving with a uniform velocity of $45 km / h$. The time taken by the train to cross a bridge of length 850 meters is

The equation of a progressive wave is $y=8 \sin \left[\pi\left(\frac{t}{10}-\frac{x}{4}\right)+\frac{\pi}{3}\right]$. The wavelength of the wave is

A short magnetic needle is pivoted in a uniform magnetic field of strength $1 T$. When another magnetic field of strength $\sqrt{3} T$ is applied to the needle in a perpendicular direction, the needle deflects through an angle $\theta$, where $\theta$ is

In a reversible isochoric change

A man of weight $80 kg$ is standing in an elevator which is moving with an acceleration of $6 m / s ^2$ in upward direction. The apparent weight of the man will be $\left(g=10 m / s ^2\right)$

What is the maximum acceleration of the particle doing the SHM $y=2 \sin \left[\frac{\pi t}{2}+\phi\right]$ where 2 is in $cm$