MCQ
The addition of $\text{HBr}$ is easiest with:
- A$\mathrm{CH}_2=\mathrm{CH}-\mathrm{Cl}$
- B$\mathrm{Cl}-\mathrm{CH}=\mathrm{CH}-\mathrm{Cl}$
- C$\mathrm{CH}_3-\mathrm{CH}=\mathrm{CH}_2$
- ✓$\left(\mathrm{CH}_3\right)_2 \mathrm{C}=\mathrm{CH}_2$
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