MCQ
The additive inverse of $\frac{-7}{19}$ is:
- A$\frac{-7}{19}$
- ✓$\frac{7}{19}$
- C$\frac{19}{7}$
- D$\frac{-19}{7}$
✓
Answer
Correct option: B.
$\frac{7}{19}$
We know that, if a and b are the additive inverse of each other,
Then $a + b = 0$
Suppose, $x$ is the additive inverse of $\frac{-7}{19}$
Then, $\text{x}-\frac{7}{19}=0$
$\Rightarrow\text{x}=\frac{7}{19}$
Hence, additive inverse of $\frac{-7}{19}$ is $\frac{7}{19}.$
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