MCQ
The additive inverse of $\frac{\text{x}^5-7{\text{x}}^2+18}{\text{x}^3-2}$​ is:
  • A
    $\frac{\text{x}^5+7{\text{x}}^2+18}{\text{x}^3-2}$
  • B
    $\frac{\text{-x}^5-7{\text{x}}^2+18}{\text{x}^3-2}$
  • $\frac{\text{-x}^5+7{\text{x}}^2-18}{\text{x}^3-2}$
  • D
    None of these

Answer

Correct option: C.
$\frac{\text{-x}^5+7{\text{x}}^2-18}{\text{x}^3-2}$

Additive inverse of any number is simply the negative of that number. For example Additive inverse of $x$ will be $-x.$
so Additive inverse of $ = \frac{\text{-x}^5-7{\text{x}}^2+18}{\text{x}^3-2}$
will be $ = \frac{\text{-x}^5+7{\text{x}}^2-18}{\text{x}^3-2}$

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