Question
The adjoint of the matrix $\left[\begin{array}{ll}1 & 2 \\ 3 & 4\end{array}\right]$ is

Answer

Let $A=\left[\begin{array}{ll}1 & 2 \\ 3 & 4\end{array}\right]$ then $| A |=\left|\begin{array}{ll}1 & 2 \\ 3 & 4\end{array}\right|$.
Now, cofactors of elements of $| A |$ are
$C_{11}=(-1)^{1+1} (4)=4$
$C_{12}=(-1)^{1+2}(3)=-3$
$C_{21}=(-1)^{2+1}(2)=-2$
and $C_{22}=(-1)^{2+2}(1)=1$
Now, adj $(A) =\left[\begin{array}{ll}C_{11} & C_{12} \\ C_{21} & C_{22}\end{array}\right]^T$
$\begin{array}{l}=\left[\begin{array}{rr}4 & -3 \\ -2 & 1\end{array}\right]^T \end{array} $
$ =\left[\begin{array}{rr}4 & -2 \\ -3 & 1\end{array}\right]$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

If $a, b, c$ are in $A.P.,$ then the determinant $\begin{vmatrix}\text{x}+2&\text{x}+3&\text{x}+2\text{a}\\\text{x}+3&\text{x}+4&\text{x}+2\text{b}\\\text{x}+4&\text{x}+5&\text{x}+2\text{c}\end{vmatrix}$
Maximize $Z=7 x+11 y$, subject to $3 x+5 y \leq 26$, $5 x+3 y \leq 30, x \geq 0, y \geq 0$.
Let f : $R \rightarrow R$ be the functions defined by $f(x) = x^3 + 5.$ Then $f^{-1}(x)$ is:
Let $f : R \rightarrow R$ be given by $f(x) = [x^2] + [x + 1] - 3$ where $[x]$ denotes the greatest integer less than or equal to $x.$ Then, $f(x)$ is:
If $\text{A}=\begin{bmatrix}\cos\theta -\sin\theta \sin\theta \cos\theta\end{bmatrix},$ then $A^T + A = I_2,$ if:
If $\text{A}=\begin{bmatrix}1&0&0\\0&1&0\\\text{a}&\text{b}&-1\end{bmatrix},$ then $A^2$ is equal to$:$
Which of the given qualities is a vector:
  1. Speed
  2. Time
  3. Weight
  4. Volume
The function $\text{f(x)}=\begin{cases}\frac{\text{x}^2}{\text{a}},&0\leq\text{x}<1\\\text{a},&1\leq\text{x}<\sqrt{2}\\\frac{2\text{b}^2-4\text{b}}{\text{x}^2},&\sqrt{2}\leq\text{x}<\infty\end{cases}$ is continuous for $0\leq\text{x}<\infty,$ then the most suitable values of a and b are:
  1. $\text{a}=1,\text{ b}=-1$
  2. $\text{a}=-1,\text{ b}=1+\sqrt{2}$
  3. $\text{a}=-1,\text{ b}=1$
  4. $\text{None os these}.$
A fair die is rolled. Consider the events $A=\{1,3,5\}, B=\{2,3\}$ and $C=\{2,3,4,5\}$. Then the conditional probability $P((A \cup B) \mid C)$ is
Choose the correct answer from the given four options.
If $|\vec{{\text{a}}}|=10,|\vec{{\text{b}}}|=2$ and $\vec{{\text{a}}}\cdot\vec{{\text{b}}}=12,$ then value of $|\vec{{\text{a}}}\times\vec{\text{b}}|$ is:
  1. 5.
  2. 10.
  3. 14.
  4. 16.