7. Alcohol, phenol and ethers — Chemistry STD 12 Science — Question

$\begin{array}{*{20}{c}}
  {\begin{array}{*{20}{c}}
  {\,\,\,\,\,\,\,\,\,C{H_3}} \\ 
  {\,\,\, \downarrow } 
\end{array}} \\ 
  {C{H_3} \to C - OH} \\ 
  {\,\,\,\,\, \uparrow } \\ 
  {\,\,\,\,\,\,\,\,\,C{H_3}} 
\end{array}$ $ \to $ $\begin{array}{*{20}{c}}
  {\begin{array}{*{20}{c}}
  {\,\,\,\,\,C{H_3}} \\ 
  | 
\end{array}\,\,\,} \\ 
  {C{H_3} - {C^ + } + O{H^ - }} \\ 
  {|\,\,\,\,} \\ 
  {\,\,C{H_3}} 
\end{array}$

Presence of $3$ alkyl group increases electron density on ${3^o}$ carbon atom.

Hence $ - OH$ group is easily removed.

After the removal of $ - OH$ group ${3^o}$ carbonium ion is formed which is most stable