MCQ
The alkene which on ozonolysis yields acetone is
- A$C{H_2} = C{H_2}$
- B$C{H_3} - CH = C{H_2}$
- ✓${(C{H_3})_2}C = C{(C{H_3})_2}$
- D$C{H_3} - CH = CH - C{H_3}$
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$I ^{-}+ ClO _3^{-}+ H _2 SO _4 \longrightarrow Cl ^{-}+ HSO _4^{-}+ I _2$
The correct statement(s) in the balanced equation is/are:
$(A)$ Stoichiometric coefficient of $HSO _4^{-}$is 6 .
$(B)$ lodide is oxidized.
$(C)$ Sulphur is reduced.
$(D)$ $H _2 O$ is one of the products.
At $t = 800\,s$, $[N_2O_5] = 1.45\,mol\,L^{-1}$
At $t = 1600\,s$, $[N_2O_5] = 0.88\,mol\,L^{-1}$
If $(n=4)$ then di-carboxylic acid. would be known as