MCQ
The angle between the vectors $(\hat i + \hat j)$ and $(\hat j + \hat k)$ is ....... $^o$
- A$30$
- B$45$
- ✓$60$
- D$90$
$\cos \theta = \frac{{\vec A.\vec B}}{{|\vec A||\vec B|}} = \frac{1}{{\sqrt 2 \times \sqrt 2 }} = \frac{1}{2}$
$\theta = 60^\circ $
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