MCQ
The angle for which maximum height and horizontal range are same for a projectile is –
  • A
    $32°$
  • $48°$
  • C
    $76°$
  • D
    $84°$

Answer

Correct option: B.
$48°$
$76^{\circ}$
$H _{\max }=$ horizontal range
$ \frac{u^2 \sin ^2 \theta}{2 g}=\frac{u^2 \sin 2 \theta}{g}$
$\frac{\sin ^2 \theta}{2}=2 \sin \theta \cos \theta=\sin \theta=4 \cos \theta \tan \theta=4 \theta=76^{\circ}$

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