MCQ
The angle of dip at the magnetic equator is-
- A0°
- ✓30°
- C60°
- D90°
✓
Answer
Correct option: B.
30°
$30^{\circ}$
Hint: $ \tan \delta=\frac{B_V}{B_H}=\frac{1}{\sqrt{ } 3} \Rightarrow \delta=\tan ^{-1}\left(\frac{1}{\sqrt{3}}\right)=30^{\circ} $
Hint: $ \tan \delta=\frac{B_V}{B_H}=\frac{1}{\sqrt{ } 3} \Rightarrow \delta=\tan ^{-1}\left(\frac{1}{\sqrt{3}}\right)=30^{\circ} $
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