MCQ
The angle of projection for a projectile to have same horizontal range and maximum height is :
- A$\tan ^{-1}(2)$
- ✓$\tan ^{-1}(4)$
- C$\tan ^{-1}\left(\frac{1}{4}\right)$
- D$\tan ^{-1}\left(\frac{1}{2}\right)$
✓
Answer
Correct option: B.
$\tan ^{-1}(4)$
b
$\frac{u^2 \sin 2 \theta}{g}=\frac{u^2 \sin ^2 \theta}{2 g}$
$\frac{u^2 \sin 2 \theta}{g}=\frac{u^2 \sin ^2 \theta}{2 g}$
$4 \sin \theta \cos \theta=\sin ^2 \theta$
$4=\tan \theta$
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